
Solution in php:
function solution($A) {
$N = count($A);
$sum = ($N + 2) * ($N + 1) / 2;
for($i = 0; $i < $N; $i++){
$sum -= $A[$i];
}
return intval($sum);
}
Given “AS IS”, can be ported from other languages from solutions found on the internet, please use with care.
Please note: we think that codility.com does not give a correct assessment of your real-world programming skills. For instance, reading the below would bring more understanding why: http://codility-test-questions.blogspot.com/2013/01/my-experience-with-codility-test.html
